Q1. Two right triangles ABC and DBC are drawn ion the same hypotenuse BC and on the same side of BC. If AC and BD intersect at P, prove that AP x PC = BP x PD.

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Similar to triangle (Part 5) | Some Applications of Trigonometry | CBSE | Class 10 | Math

Q1. Two right triangles ABC and DBC are drawn ion the same hypotenuse BC and on the same side of BC. If AC and BD intersect at P, prove that AP x PC = BP x PD.

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